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A father is 3 times older than his son and the sum of their ages is 40 years. Find their present age?

Friday, July 16th, 2010

Solution:

If we let the age of the father be “F”, and the age of the son be “S”, then we know the following:

1. F = 3 x S
2. F+S=40

Therefore, F=3x(40-F)…so 4F=120.

Therefore, F=30 and S=10.

This entry was posted on Friday, July 16th, 2010 at 4:44 am and is filed under 9th Grade, Homework Answers, Math Answers. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

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