A father is 3 times older than his son and the sum of their ages is 40 years. Find their present age?
Friday, July 16th, 2010
Solution:
If we let the age of the father be “F”, and the age of the son be “S”, then we know the following:
1. F = 3 x S
2. F+S=40
Therefore, F=3x(40-F)…so 4F=120.
Therefore, F=30 and S=10.
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