2. the constraints have not been specified and as such inputs to solve the problem are missing.

3. Let the production of bargain and deluxe monitors be x units and y units respectively for maximizing the profit

Let Z be the Objective function for maximization.

Z= 100x +150 y

The constraint for the Assembly line hours is 3x +5y ≤ 3900

Constraint for Cabinet shop hours is x+3y ≤ 2100

Constraint for Testing & Packing hours is 2x+2y≤ 2200, or x+y ≤ 1100

And of course x ≥ 0 and y ≥ 0

All these constraints are put on a graph as shown below

Value of Z = 100x+150y at ( 0,0 ) is = 0

Value of Z at (0,700) is = 105000

Value of Z at (300,600) is = 30000+90000

= 120000

Value of Z at (800,300) is = 80000+45000

= 125000

Value of Z at (1100,0) is = 110000

It is obvious from the above calculation that Z is maximum at (800, 300) that is

If production of Bargain monitors is 800 units and Deluxe monitors is 300 units

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