A 200 liter solution that is 62% acid requires 144 liters of acid and 56 liters of water.

We need to find a quantity “x” of the first solution and a quantity “y” of the second solution such that x+y=200 and .8x+.3y=0.62*200.

· .8x+.8y=160 (multiplying by .8)

· .8x+.3y=144

If we subtract the second equation from the first equation we get .5y=56, so y = 112. Therefore, x=88.