Rate at which water is pumpedin is r(t)= 20e^0.002t

This means that water pumped in time Δt will be 20e^0.002t.Δt gallons

Hence the amount of water pumped in 5 minutes, will be=

=

=10000[e^.01-1]

= 10000[1.01 -1]

= 10000 (.01)

= 100 gallons approx