(a) f(x)= ex/2,     f(0)= 1

 

     F’(x)= ½  ex/2, f ’(0)= ½

 

    F’’ (x)= ¼ ex/2 , f ‘’ (0)= 1/4

 

   F ‘’’ (x)= 1/8 ex/2 ,  f ‘’’ (0)= 1/8   ….. and so on

 

Hence Maclaurin Series will be

 

(b) f(x)= sin3x,    f(0) =0

 

     F‘(x)= 3cos3x, f ’(0)=3

 

     F ‘’(x)=-9sin3x , f ‘’(0)= 0

 

    F ‘’’(x)=-27cos3x, f ‘’’(0)=-27

 

     F4(x)= 81sin3x,     f4(0)= 0

 

    F5(x)= 243cos3x,     f5(0)=243….. and so on

 

Hence Maclaurin series will be

 

(c) f(x)=x2/2 -1+cosx,    f(0)= 0

 

     F ‘(x)=x-sinx,            f ‘(0)=0

 

     F’’(x)=1-cosx,         f’’(0)=0

 

     F’’’(x)=sinx,            f’’’(0)=0

 

      F4(x)=cosx  ,            f4(0)=1

 

    F5(x)=-sinx                f5(0)= 0

 

    F6(x)= -cosx,               f6(x)=-1…. And so on

 

Hence Maclaurin series will be

                              

                                                   ****