(a) f(x)= ex/2, f(0)= 1
F’(x)= ½ ex/2, f ’(0)= ½
F’’ (x)= ¼ ex/2 , f ‘’ (0)= 1/4
F ‘’’ (x)= 1/8 ex/2 , f ‘’’ (0)= 1/8 ….. and so on
Hence Maclaurin Series will be
(b) f(x)= sin3x, f(0) =0
F‘(x)= 3cos3x, f ’(0)=3
F ‘’(x)=-9sin3x , f ‘’(0)= 0
F ‘’’(x)=-27cos3x, f ‘’’(0)=-27
F4(x)= 81sin3x, f4(0)= 0
F5(x)= 243cos3x, f5(0)=243….. and so on
Hence Maclaurin series will be
(c) f(x)=x2/2 -1+cosx, f(0)= 0
F ‘(x)=x-sinx, f ‘(0)=0
F’’(x)=1-cosx, f’’(0)=0
F’’’(x)=sinx, f’’’(0)=0
F4(x)=cosx , f4(0)=1
F5(x)=-sinx f5(0)= 0
F6(x)= -cosx, f6(x)=-1…. And so on
Hence Maclaurin series will be
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