1. Distance
of fall = 130 ft = 39.624 meters
2. Time
taken to fall 39.624 meters:
a.
d = ½ a t2
b.
39.624 m = ½ 9.8 t2
c.
79.248 m = (9.8 m/s2) t2
d.
2.84368 s = t
3. Velocity
at d = 39.62 (just before colliding with box):
a.
v =a t
b.
v = (9.8 m/s2) (2.84368 s)
c.
v = 27.8681 m/s
4. Length
travel after impact = 18.7 inches = 0.47498 meters
5. Acceleration
while crushing the box:
a.
d = ½ (-a) t2 (we have used a
negative sign to denote deceleration)
b.
v = a
t
c.
0.47498 m = ½ a t2
d.
27.8681 m/s = a t (now we have two equations
and two unknowns)
e.
= t
f.
0.47498 m = ½ (-a) ()2
(substituting t in the first equation for distance)
g.
0.94996 m = 
h.
a = -776.630998/0.94996 m/s2
i.
a = -817.5407 m/s2
6. Time
taken to crush box:
a.
v = a t = -27.8681 m/s
b.
( -817.5407 m/s2) t = -27.8681 m/s
c.
t = 0.0340877219