The given system in the matrix format will be as follows

                   AX       = B

To find the inverse of the coefficient matrix  A=,we carry out Row operations as  follows

 

R2→R2 -3R1      and  R3→R3-9R1                 

Next R3→R3-8R2                                          

 

 

Next R2→R2-R3   and R1→R1-R3                       

 

Next R3 (R3-R2 )                                                            

 

Next R1→R1 +2R3                                                                    

 

Since we had AX = B,  A-1AX= A-1B, Hence X= A-1B = =

 

This will give x=0, y=-2 and z=-1