When the plane will be at an altitude of 14000 ft, its position can be illustrated as in the figure above. The Starting point is A and Plane is at C. Altitude of the Plane is BC= 14000 ft. ABC is a Right Triangle. The distance flown by the Plane is equal to AC

AC =14000 CSC 35.

= 14000( )

= 24411.50 ft

Now speed of the Plane is 180 ft/ sec, hence time taken to fly 24411.50 ft will be

= 24411.50/ 180 sec

=135.6 sec

= 2.26 min

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