Let m be any positive integer, whose cube is m³ . Let a and b two other positive integers such that a>b. The difference of their squares is a² –b².

It is given that m³ = a²- b²

This can be written as m³ = (a-b) (a+b).

Let a-b = m and a+b = m² . Solve for a and b.

a= (m²+m)/2 and b= (m² –m)/2.

Now we can choose any integer value for m and find out the corresponding a and b

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