This problem can be solved by using the equation of motion v2 = u2 +2fs, where u is the initial velocity, v is the final velocity, s is the distance traveled and f is the acceleration

This problem can be solved by using the equation of motion v² = u² +2fs, where u is the initial velocity, v is the final velocity, s is the distance traveled and f is the acceleration.

In the given problem the u, the initial velocity is 89km/h = 89(5/18) m/s. Final velocity is =0 as the car comes to rest after the collision. Distance traveled is s= 0.94 m.

Accordingly 0= 198025/324 +2f(.94).

Solving for f, we will have f= - 198025/324(1.88)

= -325.1 m/s²

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