The given system of equations is as follows

x/2 + y/3 = 2/3

x/2 + 2y= -1

Subtract the second equation from the first, thus eliminating x/2

y/3-2y = 2/3 +1

-5y/3= 5/3

Hence y =-1. Substitute this value in either of the two equations and solve to get x=2.

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