The two players will cross at a point where the sum of the distances covered by them equals 360 ft.

Accordingly t⁴ +54t² = 360, Or t⁴ +54t² -360=0

On factorization, it is (t²+60)(t² -6)=0

This gives t² = -60, or 6

Reject t² = -60 as not feasible, Real value is t² = 6

Or, t= √6 seconds

t= 2.45 seconds approx

At this point of time the first player would have covered a distance of t⁴ = 36 ft and the other player would have covered 54t² = 54(6) = 324 ft

As the first player is running clockwise, the two players would meet at a point between Home Plate and the third base.

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