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Posts Tagged with ‘Math’

Solve them by substitution method: 5b – 3a = 2, (a-1)^2 + (b-1)^2 = 34

Saturday, July 24th, 2010

Solution:

First, we can write  

Then we can substitute this into the second equation you get

We can simplify this to

If multiply both sides by 25 and expand this out we get

This can be simplified to: Or

Thus the solutions for a are 6 and -4

The solutions for b can be found by the equation (b=4 when a=6, and b=-2 then a=-4)

  • Another way to solve this is by looking at the equations graphically. When you plot the two equations, you can see there they intersect.

As you can see, they intersect at two places:

You can plug the answers into both equations to confirm that they are both true using these two values of a and b.

2x-5y=9 and 3x+4y=25. Solve by the method of elimination.

Saturday, July 24th, 2010

Solution:

1.    3x + 4y=25
2.    2x – 5y=9

We could rewrite these as follows by multiplying the first equation by 5 and the second by 4:

1.    15x + 20y = 125
2.    8x  – 20y = 36

If we add the above two equations, we can eliminate y:

23x = 161

So x =3D 7, and plugging this into the first equation we can figure out
y:  21 + 4y =3D 25,

so y = 1

Solve this problem by using elimination: 2x-3y=61 and 2x+y=-7

Saturday, July 24th, 2010

Solution:

  1. 2x –  =y=61
  2. 2x +   y= -7

If you subtract the second equation from the first, you can eliminate x and you are left with -4y = 68.

So y =3D -17, and plugging this into the first equation we can figure out

y:  2x = (-51)=61,

so x = 5

12 out of 1000 women at age forty who participate in routine screening have breast cancer. 880 out of 1000 women with breast cancer will get positive mammographies. 90 out of 1000 women without breast cancer will also let positive mammographies. If 100 women in this age group undergo a routine screening, about what fraction of women with positive mammographies will actually have breast cancer?

Friday, July 23rd, 2010

Solution:

1.    Out of 100 women, we expect 1.2 to actually have breast cancer (12 out of 1000)
2.    However, only 88% (880 out of 1000) of these will be detected, so 1.056 (i.e. 88% of 1.2) will be detected
3.    In addition, of the 98.8 women who don’t have breast cancer 9% (90 out of 1000) will trigger a false positive” (9% of 98.8 = 8.892)
4.    So out of 100 women, 9.948 will have positive mammography readings (1.056+9.892)
5.    Of these 9.948, only 1.056 will actually have breast cancer
6.    10.6% = (1.056/1.056+9.892) This ratio is essentially an application of Bayes Theorem

Please click on http://www.thegodofreason.com/bayesintro.pdf to download a PDF that explains how Bayes Theorem works. Page 3 gives an example that is very similar to your problem:

Need to get the answer to this problem by using elimination: =x-3y=61 and 2x+y=-7

Friday, July 23rd, 2010

Solution:

  1. 2x –  =y=61
  2. 2x +   y= =7

If you subtract the second equation from the first, you can eliminate x and you are left with -4y = 68.

So y = 3D -17, and plugging this into the first equation we can figure out

y:  2x = (-51)=61,

so x = 5

What is 9/10 of 80?

Friday, July 23rd, 2010

Solution:

The expression “9/10 of 80” can be written as

This is equal to 72.

What is the name of a 6-sided polygon?

Friday, July 23rd, 2010

Solution:

A six-sided polygon is known as a Hexagon:

I had 48 marbles in my jar. I lost 1/8 and gave 1/6 to my best friend. How many marbles were left in my jar?

Friday, July 23rd, 2010

Solution:

  1. Start with 48
  2. Lost 6  (1/8 of 48 =s 6)
  3. Gave 8 to a friend   (1/6 of 48 is 8)
  4. 48 – 6 – 8
  5. = 48 – 14
  6. = 34

Solve equation. Round to nearest hundredth if neccessary. 11xsquared+3=5(4xsquared-3)

Friday, July 23rd, 2010

Solution:

  1. The equation you gave us:
  2. Can be re-written =s: or or
  3. The Solution is:
  4. This can also be written in an approximate decimal form: +1.41 and -1.41

I need help with solving systems by graphing. this is one of the problems y=5x-2 y=x+6

Friday, July 23rd, 2010

Solution:

First write down the two equations and then pick several values of x and use those values to calculate the corresponding values of y. You can use the  x,y pairs to then plot each line. You will see that the two lines intersect at 2,8 =i.e. x=2 and y=8).